English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories
0

May i please ask someone to help me out with finding the vertex, line of symmetry, the maximum or minimum value of the quadratic function: f(x)=4x^2-24x+41. Thank you so much!

2007-06-10 15:20:18 · 2 answers · asked by Princess 1 in Science & Mathematics Mathematics

2 answers

Step 1: put into parabola form by factoring and completing the square

y=4x^2 -24x +41
y-41 = 4x^2 -24x
y-41 = 4(x^2 -6x)
y-41+36 = 4(x^2-6x+9)
y-5 = 4(x-3)^2

vertex: (3,5)
parabola opens up (because there is no negative in front of the 4) therefore the minimum is the vertex (3,5)and the maximum is infinity.
line of symmetry: x=3

2007-06-10 18:56:41 · answer #1 · answered by math_angel09 2 · 0 0

Minimum value is where 8x-24=0 or x=3
This should also be the line of symmetry; if you "folded" the function to the right of this line over the line, it would overlay the function to the left of the line

2007-06-10 22:37:12 · answer #2 · answered by cattbarf 7 · 0 0

fedest.com, questions and answers