-7[4x-(x-5)] + 2x = 3-x solve for x. thanks!
2007-06-10 13:11:45 · 4 answers · asked by wade 2 in Science & Mathematics ➔ Mathematics
-7[4x-(x-5)] + 2x = 3-x
-7(4x - x + 5) + 2x = 3 - x
-28x + 7x - 35 + 2x = 3 - x
Add x = 3 to each side:
-28x + 7x - 35 + 2x - 3 + x = 0
Add x terms and absolute terms:
-18x - 38 = 0
Add 38 to each side:
-18x = 38
Divide by -18:
x = -38/18 = -19/9.
2007-06-10 13:23:52 · answer #1 · answered by Anonymous · 0⤊ 0⤋
-7[4x-(x-5)] + 2x = 3-x
-7[4x-x+5] + 2x = 3-x
-7[3x+5] = 3-x - 2x
-21x - 35 = 3 - 3x
-21x + 3x = 3 + 35
-18x = 38
x = -38/18
x = -19/9
x = -2 1/9
2007-06-10 20:23:26 · answer #2 · answered by Kemmy 6 · 0⤊ 0⤋
-7[4x-(x-5)] + 2x = 3-x
-28x +7x +35 +2x = 3 -x
-28x+7x+2x+x= 3-35
-10x= -32
x = 3.2
2007-06-10 20:18:01 · answer #3 · answered by ironduke8159 7 · 0⤊ 1⤋
-7[4x-(x-5)]+2x=3-x
-7[4x-x+5]+2x=3-x
-7[3x+5]+2x=3-x
-21x-35+2x=3-x
-19x-35=3-x
-19x+x=3+35
-18x=38
-x=38/18
x=-19/9
2007-06-10 22:33:04 · answer #4 · answered by sam 3 · 0⤊ 0⤋