expression: Tn=ar^n-1 to log form Thanks!
2007-06-10 12:31:14 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
sorry fogot to say isolate "n"
2007-06-10 12:40:43 · update #1
Assume T = a.r^(n - 1)
T/a = r^(n - 1)
log (T/a) = (n - 1).log r
n - 1 = log (T/a) / log r
n = log(T/a) / log r + 1
2007-06-11 08:27:02 · answer #1 · answered by Como 7 · 0⤊ 0⤋
Where numbers are multiplied, their logs are added to give the log of the product.
Where a number is raised to a power, the log of the number is multiplied by the power to give the log of the result.
log(Tn) = log(a) + (n - 1)log(r).
2007-06-10 12:38:45 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Tn = ar^(n-1)
lg(Tn) = lg[ar^(n-1)]
lg(Tn) = lg(a) + lg(r^(n-1))
lg(Tn) = lg(a) + (n-1)lg(r)
2007-06-10 13:51:05 · answer #3 · answered by Kemmy 6 · 0⤊ 0⤋