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1. If a gas is compressed from 4 L to 1 L and the temperature remains constant, what happens to the pressure?

2. Describe what happens to the volume of a balloon when it is taken outside on a cold winter day. Explain why this happens.

3. Calculate the volume of a gas (in L) at a pressure of 1.00 x 10(exponent 2) kPa if its volume at 1.20 x 10(exponent 2) kPa is 1.50 x 10(exponent 3) mL

4. A gas with a volume of 3.00 x 10(exponent 2) mL at 150.0 degree celcius is heated until its volume is 6.00 x 10(exponent 2) mL. What is the new temperature of the gas if the pressure remains constant during the heating process?

2007-06-10 11:29:16 · 2 answers · asked by Got Tea? 2 in Science & Mathematics Chemistry

2 answers

1. It increases to four times the previous value.

2. It shrinks. The temperature goes down, so the pressure and volume do too.

3. 4. You have to be kidding. Never will I carry out all those calculations on one question. Take your winnings and go.

2007-06-10 11:37:42 · answer #1 · answered by steve_geo1 7 · 0 0

1. using equation PV=P1V1
if the gas is decrease from 4L to 1L, then the pressure will increase 4 times what it was

2. in cold temperatures, the molecules inside the balloon slow down because it loses energy. slow moving particles cause less collisions and thus lowers the pressure inside, so the volume decreases.

3. same equation as above
1.2 x 10^2 x 1.5 x 10^3 = 1 x 10^2 x (unknown volume)
if you solve it, the volume is 1.8 x 10^3

4. PV/T = P1V1/T1
so reduces to V/T = V1/T1
3x10^2 / 150 = 6x10^2 x (new temp)
so solve and you should get new temperature = 300 degrees

2007-06-10 11:40:56 · answer #2 · answered by runnerforlife0890 2 · 0 0

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