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I'm in AP chem & we've got a final next week... She gave us a bunch of problems to practice but won't help us with the ones we dont get. Maybe someone could help me here?

1. A mixure of 1 mol each of CO, H2O & CO2 is introduced into a 10 L flask @ a temp. at whcih K = 10 for the reaction...
CO + H2O <-> Co2 + H2 ....Kc= 10
When it reaches eq.
a) the amount of H2 will be 1 mol
b) the amount of CO, H2O & H2 will each be less than a mol
c) the amonts of all reactnts & products will be greater than a mol
d) the amounts of CO2 & H2 will each be greather than a mol and Co & H2O will each be less than 1 mol

2) Pure liquid HCl is a poor electrial conducotr., So is pure liquid water. when these 2 liquids mix the result solution conducts electir currect very well. how do you explain this?

3) A method of removing excess solutes from a colloidal mixture is a) distillation b) recrystallization c) dialysis or d) gas chromatography

thank you so much!

2007-06-10 11:03:16 · 1 answers · asked by suggargurl302 2 in Science & Mathematics Chemistry

1 answers

[CO2][H2]/[CO][H2] = 10

[CO2][H2] = 10[CO][H2]

a.) No. It will be much less than that
b.) No. CO will be less than a mole, but CO2 and H2 will be greater.
c.) No, because of the factor of 10
d.) True, because it takes multiplying by 10 to make [CO][H2] equal to [CO][H2O]

2. HCl(l) or HCl(g) + H2O ===> H3O+ + Cl-

3. Dialysis. Solvent crosses thesemipermeable membrane. Colloidal particles do not.

2007-06-10 12:32:34 · answer #1 · answered by steve_geo1 7 · 0 0

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