How would I factor this --->
2(x-1)(x+3)
Thanks for the help.
2007-06-10 09:59:15 · 7 answers · asked by sofiee 1 in Science & Mathematics ➔ Mathematics
Its already factored.
To expand
2x^2 + 4x - 6
2007-06-10 10:03:36 · answer #1 · answered by physical 4 · 0⤊ 0⤋
First expand.
2[x^2 + 3x - x - 3]
2[x^2 +2x -3]
2x^2 + 4x -6
now factor with any method you like, I prefer to use this method..
box method:
factors of 2 (first term coefficient) is 2 X 1
factors of -6 (third term coefficient) is 6 X -1
place factors of one number in a column
2 6
1 -1
if you multiply diagonally and add them up (2x-1 + 1x6) and they equal the second term coefficient (4) then its works
so now you plug them in by
readign the box by rows and placing x on the numbers in the first column
2x 6
1x - 1
now just put brackets around each row
(2x 6)
(x - 1)
to become (2x +6)(x-1)
2007-06-10 17:08:16 · answer #2 · answered by Malvern100 1 · 0⤊ 0⤋
You don't need to. It is already factored. There are no "multiples" of any term that would allow you simplify any further.
2007-06-10 17:02:04 · answer #3 · answered by RG 3 · 1⤊ 0⤋
2(x-1)(x+3)=
2(x^2+2x-3)
2x^2+4x-6
2007-06-10 17:19:36 · answer #4 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
its already factored, you cannot factor it out more
2007-06-11 01:07:19 · answer #5 · answered by Anonymous · 0⤊ 0⤋
If you do the FOIL method, you will get:
4x^2 + 4x - 12
2007-06-10 17:05:57 · answer #6 · answered by mdjohns7 1 · 0⤊ 1⤋
2(x-1)(x+3)
=(2x-2)(x+3)
=2x^2+6x-2x-6
=2x^2-2x+6x-6
=2x(x-1)+6(x-1)
=(2x+6)(x-1)
2007-06-10 17:20:56 · answer #7 · answered by fofo m 3 · 0⤊ 0⤋