Chemistry Homework...please help!?

Question

A sealed bottle of water with capacity 250 mL contains 248.0 mL of water at 0 degrees C. If it freezes, will the container rapture. Please show calculations.

Thanks for your help!

Answer 1

I'll assume you mean 'rupture' (break apart), and not 'rapture' (join the choir of heavenly angels come Armageddon).

Water expands its volume by ~9% on freezing at 0C and atmospheric pressure. This would give the ice a volume of (248 ml * 1.09) = 270.3ml, substantially larger than the capacity of the bottle. Thus, for the water to freeze, the bottle would have to rupture.

Answer 2

water is somehow a strage material which has a highest density at 4 degrees centigrate as 1g/ml

so when it freezes its density becomes lover and its volume gets higher.

the density of ice (encarta) at 0 degrees is 0.917 g/ml
while density of water at that temperature = 0.9998 g/ml

lets find the mass of water:
248ml*0.9998g/ml= 248g

mass of the water will remain constant it wont change during the freezing so lets calculate the colume after freezing:

m=d.v
m=mass
d=density
v=volume
248 = 0.917.v
v= 248/0.917 = 270.45 ml so it exceeds the colume of the bottle and result the container rupture.

Answer 3

Yes because that leaves 12 ML left and at that temperature rate it would rapture.