how do you graph?

Question

3x-y is greater then or equal to 2

Answer 1

First get your inequality into slope-intercept form:

3x-y>2

-y>-3x+2

Remember, if you divide by a negative number, you must switch the sign.

y<3x-2

Now graph it just like any other line, except that since this is less than or equal to, the line would be solid.

Now use a solution set that is not on the line. Try (0,0)

0<3(0)-2

0<-2?

The inequality is false, therefore, shade in the region where (0,0) does not lie.

Hope this helps.

Answer 2

First off, write out the equation in the form y ≥ 3x, so that it looks more familiar. Then plot this line on a graph, and shade in the area where the equation is greater than or equal to 2 if you plug the coordinates into the formula.

Sorry for the vague explanation...

Answer 3

3x - y >= 2
3x - y + y >= 2 + y
3x >= 2 + y
3x - 2 >= 2 - 2 + y
3x -2 >= y which is identical to y <= 3x - 2 (standard form of a linear equation)

Find two points on the line: (1) If x = 0, then y = 3(0) - 2 = -2;
so the point (0,-2) is on the line
(2) If x = 1, then y = 3(1) - 2 = 1
so the point (1,1) is on the line
Using an x-y graph, plot the two points above and draw a line between and through them.

Then shade the area to the left of the graph ( --> less than).

Answer 4

Just graph the line 3x-y =2
This is a line with slope 3 and y-intercept -2.
Now shade everything above the line including points on the line. The shaded are indicates the location of all points that satisfy the inequality.

Answer 5

graph the line3x-y (which is really really y=3x) and graph the line y=2 (should be a horizontal line). Anywhere that the 3x line is above the 2 line, it is greater than the 2 line

Answer 6

if 3x-y>2 then 3x-2>y or y<3x-2

Graph the line 3x-2, then you want everything below this line...

Check: pick a point in the region and plug in the values,,, it should make the inequality true