evaluate the following expression. let a=2,b=5,and c=1 -3a+2(b2+c)
2007-06-10 08:10:32 · 4 answers · asked by jessys 1 in Science & Mathematics ➔ Mathematics
To evaluate this algebraic expession, replace each variable with the value of each variable, as such:
-3(2)+2(5^2+1)
Now do order of operations, or PEMDAS
-3(2)+2(25+1)
-6+2(26)
-6+52
The answer is 46
Hope this helps.
2007-06-10 08:17:45 · answer #1 · answered by edgehead_11071981 2 · 0⤊ 0⤋
a=2,b=5,and c=1
-3a+2(b2+c)
= -3(2) +2(5^2 +1)
= -6 +2(25+1)
=-6 +2(26)
= -6 +52
= 46
2007-06-10 08:17:28 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
substitute
-3*2 + 2*(5^2 + 1)
evaluate
-6 + 2*(26)
-6 + 52
46
2007-06-10 08:15:09 · answer #3 · answered by teacher2006 3 · 0⤊ 0⤋
(-3a)/+2/(b2+c)
(-3a)= (-6) (-6)+2= (-4) b2= 10+1= 11
(-4)11= (-44)
2007-06-10 08:18:39 · answer #4 · answered by Anonymous · 0⤊ 0⤋