Write the following expression in equivalent form as a single algebraic fraction.?

Question

(2x^2 / 5) (10 / 7x) + 2 / x

I got 20x^2 + 70 / 35x. Is this correct? Can it be anymore simplified? Please show your steps on how you obtained your answer and try not to make to wordy while you're at it cause I get intimidated by anything too wordy.

Answer 1

(2x^2 / 5) (10 / 7x) + 2 / x =
20x^2/35x + 2/x =
(20x^2 + 70) / 35x
this is where you ended, now simplify by dividing top/bottom by 5
= (4x^2 + 14) / 7x

Answer 2

The answer you gave isn't a single algebraic fraction. Working it out goes like this:

cancel the divided by 5 and times ten to be times two

(2x^2*2)/7x + 2/x

multiply the twos on the left, multiply the right by 7/7 to get the denominators to be the same

4x^2/7x + 14/7x

add them together

(4x^2 + 14)/7x

Answer 3

(2x^2 / 5) (10 / 7x) + 2 / x
(2x^2 * 10)/(5 * 7x) + (2 / x)
4x/7 + 2/x
4x^2 /7x + 14/7x
(4x^2 + 14)/7x

If you take your answer of 20x^2 + 70 / 35x and divide the top and bototm by 5, you'll get the same.

Answer 4

(2x^2 /5) (10/7x) + 2/x = 20x^2 / 35x + 2/x = 20x^2 + 70 / 35x

Dividing by 5, we get

(4x^2 + 14) / 7x

So, you did well to get a right answer and only one more step of simplification is possible as shown above.

Answer 5

It is correct - it can be simplified further by taking a 5 out from the numerator to give:-

[5 ( 4x^2 + 14) ] / [5 * 7 * x]
5 gets cancelled from the numerator and denominator to give
(4x^2 + 14) / 7x

Answer 6

(2x^2/5)(10/7x) +2/x
= 20x^2/35x +2/x
4x^2/7x+2/x
=4x^2/7x +14/7x
=(4x^2 +14)/(7x)
= 2(2x^2+7)/(7x)

Answer 7

(2x^2/5)(10/7x)+(2/z)=
(20x^2 / 35x) + 2/z=
(20x^2z+2)35xz

Answer 8

(4x^2 + 14) / 7x
which can be factored to
(2(2x^2 + 7)) / 7x

Answer 9

(4x^2+14)/7x