More Math Please help?

Question

A bell rings every 2 hours, a second bell rings every 3 hours, and a third bell rings every 4 hours. If all 3 bells ring at 9:00 AM. , at what time will all 3 bells next ring?

Answer 1

Well, the first bell will ring again in 2, 4, 6, 8...etc. minutes...multiples of 2. The second bell rings every 3 hours, so it will ring on multiples of 3. The third bell rings on multiples of 4. To find when they will next all ring, you need to find the least common multiple. That would be 12, in this case, so they'll next ring again in 12 hours, or at 9:00 PM

Answer 2

The bells will ring at the same time when the time is a common multiple of 2, 3, and 4. The smallest number that is a multiple of 2, 3, and 4 is 12. Therefore, the bell will ring every 12 hours.

If the bells ring at 9 am, then they will all ring again at 9 pm.

Answer 3

Seeing that one bell rings every 4 hours and anothr rings every 2 hours, you know by math that when the 4 hour bell rings the 2 hour bell rings. Now you need to see when the 4 hour and 3 hour bell rings. Seeing that the only common factor they have it 12 (3 x 4) you know that the all the bells will ring 12 hours from 9am or at 9pm.

Answer 4

Let N be the number of hours when they all ring together again. The LCM of 2, 3 and 4 will be the answer. That is 12 hours. So, the bells will ring again together at 9.00 PM.

Answer 5

To solve this problem, you need to find the LCM of 2,3,4. The LCM is 12. so every 12 hours, the bell will ring.
So next, the bells will ring at 9:00 pm.

Answer 6

9:00 AM
First bell will ring at 11:00 AM, 1:00 PM, 3:00 PM, 5:00 PM, 7:00 PM, 9:00 PM
Second bell will ring at 12:00 Noon, 3: 00 PM, 6:00 PM, 9:00 PM
Third bell will ring at 1:00 PM, 5:00 PM, 9:00 PM

You can see that all the three bells will ring together at 9:00 PM again