2007-06-10 05:32:52 · 5 answers · asked by lindasalicea 1 in Science & Mathematics ➔ Mathematics
f(x) = -x^3 + x^2 + 3x + 4
f(-1) = -(-1)^3 + (-1)^2 + 3 * (-1) + 4
= 1 + 1 -3 +4
=3
f(0) = -(0)^3 + (0)^2 + 3 * (0) + 4
= 4
f(1) = -(1)^3 + (1)^2 + 3 * (1) + 4
= -1+1+3+4
=7
2007-06-10 05:36:03 · answer #1 · answered by Sam 2 · 0⤊ 0⤋
f(x)= -x^3 + x^2 + 3x + 4
substitute values of x,
f(-1)= 1 + 1 + (-3) + 4 = 3
f(0)= 0 + 0 + 0 + 4 = 4
f(1)= -1 + 1 + 3 + 4 = 7
2007-06-10 12:46:58 · answer #2 · answered by Enginurse 2 · 0⤊ 0⤋
f(x) = -x^3 +x^2 +3x + 4
f(-1) =-(-1)^3 +(-1)^2 +3(-1) +4 = 1+1-3+4 = 3
f(0) = 0+0+0+4 = 4
f(1) = -1 +1 +3 +4 = 7
2007-06-10 12:41:00 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋
f(-1),f(0), and f(1) are 3, 4, 7 respectfully.
Note that one can read your equation as
- (x ^ 3) + x^2 + 3x + 4 or (- x) ^ 3 + x^2 + 3x + 4. However, in both cases the answer to your question is the same.
2007-06-10 12:40:11 · answer #4 · answered by Hakuna Matata 2 · 0⤊ 1⤋
f(-1):
Sub x = -1
f(-1) = -(-1)^3 + (-1)^2 + 3(-1) + 4
f(-1) = 1 + 1 - 3 + 4
f(-1) = 3
f(0):
Sub x = 0
f(0) = 4
f(1):
Sub x = 1
f(1) = -(1)^3 + (1)^2 + 3(1) + 4
f(1) = 7
2007-06-10 12:37:44 · answer #5 · answered by Anonymous · 0⤊ 0⤋