4y > - 8
3t -4 ≤ 5
2a -5 < 5 - 3a
2 > 3t + 2
3t +2 > 14
2007-06-10 04:46:48 · 7 answers · asked by numbheart_icemaiden 1 in Science & Mathematics ➔ Mathematics
4y > - 8
4y / > - 8 / 4
y > - 8 / 4
y > - 2
- - - - - - - -
3t - 4 ≤ 5
3t - 4 + 4 ≤ 5 + 4
3t ≤ 9
3t / 3 ≤ 9 / 3
t ≤ 9 / 3
t ≤ 3
- - - - - - - -
2a - 5 < 5 - 3a
2a - 5 + 3a < 3 - 3a + 3a
5a - 5 < 5
5a - 5 + 5 < 5 + 5
5a < 10
5a / 5 < 10 / 5
a < 10 / 5
a = 2
- - - - - - - - -
2 > 3t + 2
2 - 2 > 3t + 2 - 2
0 > 3t
0 / 3 > 3t / 3
0 / 3 > t
0 > t
- - - - - - - -
3t + 2 > 14
3t + 2 - 2 > 14 - 2
3t > 12
3t / 3 > 12 / 3
t > 12 / 3
t > 4
- - - - - - - - - -s-
2007-06-10 05:02:39 · answer #1 · answered by SAMUEL D 7 · 0⤊ 0⤋
1) y > -2
2) 3t ≤ 9
t ≤ 3
3) 5a < 10
a < 2
4) 0 > 3t
0 > t
5) 3t > 12
t > 4
2007-06-10 04:53:55 · answer #2 · answered by Lilovacookedrice 3 · 0⤊ 0⤋
y>-8/4
y>-2
3t ≤9
t≤9/3
t≤3
2a+3a<5+5
5a<10
a<2
2-2>3t
0>3t
t<0
3t>14-2
3t>12
t>4
2007-06-10 04:54:47 · answer #3 · answered by Anonymous · 0⤊ 0⤋
a. 4y>-8
Because dividing by positive #, sign(>,<) does not change.
y>-2
b. 3t-4 ≤ 5
3t≤9
t≤3
c. 2a-5< 5-3a
2a+3a< 10
5a< 10
a< 2
d. 2> 3t+2
0> 3t
t<0
e. 3t+2>14
3t> 12
t>4
2007-06-10 05:33:06 · answer #4 · answered by abcd 2 · 0⤊ 0⤋
3 <= x + 5 < 19 - x potential 3 <= x + 5 and x +5 < 19 - x so fixing each and every seperately provides -2 <= x from the 1st inequality and 2x < 14 from the 2d giving -2 <= x < 7 whilst recombined
2016-10-07 05:49:22 · answer #5 · answered by ? 4 · 0⤊ 0⤋
solve it like solving equations,
just don't forget to reverse the inequality sign whenever you divide by a negative number :)
2007-06-10 04:55:07 · answer #6 · answered by regreg 3 · 0⤊ 0⤋
y>-4
t<3 (less than or equal to)
dotn feel liek doing the other oens/
2007-06-10 04:51:36 · answer #7 · answered by blondecoley 4 · 0⤊ 0⤋