find the distance between the points (-3,-2) and (1,4)?

Answer 1

(-3,-2) (1,4)

1-(-3)= 4
4-(-2)=6

(4, 6)

Answer 2

Draw a line to the right from (-3,-2) and straight down from (1,4), stopping each line where the two lines intersect (1,-2). Then draw another line between your two original points. Now, what do you have? You have a right triangle.

Do you know the Pythagorean Theorem?

The distance you want is the length of the hypotenuse of a right triangle whose other sides have a length of 4 (1 - (-3)) and 6 (4 - (-2)).

Do you see how learning one thing can help you in other areas?
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Answer 3

Hi,

I can't enter the formula I used easily, but it works in the same way as Pythagoras' theorem.

Pythagoras' theorem states that c^2=a^2+b^2

c= unknown side (i.e. the distance we are trying to find)

Distance between -3 and 1 is 4 so a=4
Distance between -2 and 4 is 6 so b=6

Using Pythagoras' theorem:

c^2=4^2 + 6^2=16 + 36

This means c^2 = 52
so c = sqrt 52 (sqrt 52 = 2 sqrt 13)

Hope this helps ;-)

Answer 4

Easy. (-3,-2) would be (-x1 -x2). (1,4) would be (y1, y2). Don't forget that the 1s and 2s should be written below the variables, as a subscript, not as exponents, or else you'll end up having the wrong answer.

So, you now have : 4-1 over -3-2, which is = 3 over -5. Neither cannot be divided, so you would still have 3/-5 as the final answer.

Please correct me if I have been wrong. I hope this has helped though. :-)

Answer 5

the distance between two points is calculated by the formula

d = \/x2 - x1 ^2 + y2 - y1 ^2, where (x1, y1) and (x2, y2) are co-ordinates of the points between whom distance is to be found.

Using this the distance is d = \/[1 - (-3)]^2 + [4 - (-2)^2]
i.e. \/ 16 + 36 = \/52 = 2 \/13 units.

Answer 6

(1+3)+(4+2)
(4)+(6)
10

Answer 7

I think it is:
Square root of : (x2-x1)squared + (y2-y1)squared
e.g.
(-3-1)sqaured + (-2-4)squared
16+36=52
Square root of 52 is like 7.211102550928.
(This is the length of a line formula)