sry if this is any inconvenience 2 u but i really dont understand this question...im been forced 2 go into high school math (eewww) and (obviously) im not in high school, consequently, i suck @ this stuff. so help me, please!!! take pity on a poor 8th grade grl!!
What real numbers are excluded from the domain of the following function?
g(x)=7x+12/x(squared)+3x+7
the slash in the middle means divided by
thank u soooo much!
2007-06-10 02:40:42 · 6 answers · asked by Anonymous in Education & Reference ➔ Homework Help
Hi there. :) Basically, don't let the g(x) fool you. This is just like any other fraction; and in fractions, the only numbers that can't be used (i.e the numbers that must be excluded from the domain of a function) are numbers that would make the denominator equal zero, because you can't divide anything by zero. So in this function...
g(x) = (7x + 12) / (x^2 + 3x + 7)
All you actually have to look at is the denominator, which is:
x^2 + 3x + 7
so let x^2 + 3x + 7 = 0, and solve for that equation. That's your answer!
(If you need help figuring out real numbers -- and I only add this footnote because I did, heh -- wikipedia has a pretty thorough explanation: http://en.wikipedia.org/wiki/Real_number)
Hope that helps! :)
2007-06-10 05:04:43 · answer #1 · answered by Anonymous · 1⤊ 0⤋
I don't think any real numbers would be excluded from the domain for this function. I tried some obvious ones such as 0, -1 -2, up to -5 and they all work. good luck
2007-06-10 02:50:10 · answer #2 · answered by 16oeoj 4 · 0⤊ 0⤋
Get rid of the X by dividing both sides of the equation by X
g=7+12(squared)+3+7 then
g=7+12(squared)+10 then
g=12(squared)+17 then
divide both sides by 17
g/17=12(squared)
Solve the rest and you will have the answer.
2007-06-10 02:55:44 · answer #3 · answered by MsAdviseALot 3 · 0⤊ 0⤋
This binomial is the version of two squares: First term sq. selection -- 2nd term sq. selection Its components are consistently: (sq. Root of First term +/- sq. Root of the 2nd term) y^2 - a million = (y+a million) (y-a million)
2016-11-10 00:04:59 · answer #4 · answered by ? 4 · 0⤊ 0⤋
May talk with the school counselor and ask if you can take Business Math it easier. This looks like hard stuff to me.
2007-06-10 02:50:34 · answer #5 · answered by Snaglefritz 7 · 0⤊ 0⤋
Maybe this link will help you figure it out.
Good Luck!
2007-06-10 02:47:31 · answer #6 · answered by unknown friend 7 · 0⤊ 0⤋