Use this theory:
If a point P(x, y) divides a line segment joining points A(x1, y1) and B(x2, y2) in a ration m : n internally, Then,
x = (mx2 + nx1)/(m + n)
y = (my2 + ny1)/(m + n)
Now solve your problem:
Here,
x1 = 1
x2 = -1
y1 = 2
y2 = -4
m = 2
n = 3
Let the point dividing the line segment be P whose co-ordinates are (x, y)
Now find x and y with the given formula and thereby the co-ordinates of P. You have all the info you need. Distance isn't necessary.
x = [2(-2) + 3]/ 2 + 3
x = -1/5
y = [2(4) + 3(2)]/5
y = 14/5
The co-ordinates of the point are (-1/5, 14/5)
2007-06-10 01:00:29
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answer #1
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answered by Akilesh - Internet Undertaker 7
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If you take the points, and consider only one of the co-ordinates at a time, you get:
x: -2, 1
y: 4, 2
You don't actually need to use the distance formula here.
Basically, in total there will be 5 sections, correct?
So, the first section is 2/5 of the way, and the latter 3/5.
Just deal with the x and y separately.
x:
The distance between -2 and 1 is 3, and 2/5 of this is 6/5.
Therefore, the x-co-ordinate will be at -2 + 6/5, which is -4/5.
y:
The distance between 4 and 2 is 2, and 2/5 of this is 4/5.
Therefore, the y-co-ordinate will be at 4 - 4/5, which is 3 1/5.
Thus, your co-ordinates are:
(-4/5, 3 1/5)
2007-06-10 00:28:08
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answer #2
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answered by Anonymous
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no it's not relevant.
just divide it vertical separation and horizontal separation between the 2 points by the ratio desired (2:3).
by my math that means the co-ord is (-0.2,2.8).
2007-06-10 00:24:31
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answer #3
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answered by Anonymous
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USE SECTION FORMULA.
X = [ m(X1) + n(X2) ] / (m+n)
Y = [ m(Y1) + n(Y2) ] / (m+n)
WHERE
(X1,Y1) & (X2,Y2) ARE COODINATES WHICH ARE JOINED
AND n:m IS THE RATIO OF INTERNAL BIJECTION.
SO , YOUR QUESTION
X = [3(1) +2(-2)]/(2+3)
= -1/5
&
Y = 14/5
THE COORDINATES ARE(-1/5 , 14/5)
SO DISTANCE FROM (1,2) IS
SQRT(52/25)
2007-06-10 00:31:40
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answer #4
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answered by CURIOUS SID_B 2
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You are right. The number (2√13)/5 comes to me, but I am stymied how to use it.
http://www.mathworld.wolfram.com
2007-06-10 00:18:54
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answer #5
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answered by Anonymous
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