Physics. Total Resitance. Can u solve my cicuit?

Question

Plz check this link to see my circuit.
http://img124.imageshack.us/img124/9342/12631269km1.png
Can u solve it?
It's very important.
Every <
find RT=?

thnx

Answer 1

RT=10 Ohms

the two resistors in the middle do not count because there is no potential difference across them.

so Rt= 1 / [(1/40)+(1/20)+(1/40)]

Answer 2

Considering the circuit as if there are three branches; the top and bottom having four 10 ohm resistors and the middle one having two 10 ohm resistors, the effective resistance R is found from

1/R = 1/40 + 1/ 20 + 1/40 = 1/10

R = 10 ohm.


Considering the symmetry of the circuit it can be seee that the pd across the left out resistors will be the same for any potential across AB,

Hence the answer is 10 ohm.

Answer 3

I get RT = 5 ohms. I imagined a 10 volt battery was connected across a and b. Then I used Kirchoff's Loop Rule and Point Branch rule to generate three equations with three unknowns that were currents in various branches of your resistor network. I solved for the current out of my imaginary 10 volt battery, then used ohm's law to find the total resistance of your network.

You should build your circuit and test it out!

Answer 4

The Ans is 10 ohms. Total resistance of the circuit is 10 ohms, WHEATSTONES BRIDGE BALANCE CONDITION is the underlying principle....

Answer 5

Call the midpoint c. Then
1/3R + 1/R + 1/3R = 1/Rac
(1 + 3 + 1)/3R = 1/Rac
Rac = 30/5 = 6Ω
Rcb = Rac
Rab = 12Ω