y = 3cos(5x)
y'= -15sin5x
2007-06-09 17:58:00 · 7 answers · asked by Kendra 3 in Science & Mathematics ➔ Mathematics
thx everybody!
& yeah y' = dy/dx...i was too lazy to type it out :P
2007-06-09 18:07:22 · update #1
It's correct
2007-06-09 18:01:12 · answer #1 · answered by Don Danielo 2 · 0⤊ 0⤋
That looks 'bout right to me ☺
Doug
Edit: y' = dy/dx so the dx is --not-- missing ☺
2007-06-09 18:01:59 · answer #2 · answered by doug_donaghue 7 · 2⤊ 0⤋
you youre right
y= 3 cos (5x)
dy/dx = -3sin(5x) * 5
= -15sin(5x)
2007-06-09 18:03:45 · answer #3 · answered by Anonymous · 0⤊ 0⤋
most of it
you're missing the dx at the end
gotta give math some respect! (gotta show what you're differentiating with respect to what variable, and you should respect math!)
2007-06-09 18:01:59 · answer #4 · answered by (+_+) B 4 · 1⤊ 2⤋
way 2 go
2007-06-09 19:09:54 · answer #5 · answered by Nishant P 4 · 0⤊ 0⤋
its correct
2007-06-09 18:04:42 · answer #6 · answered by Anonymous · 0⤊ 0⤋
perfecto, good job!
2007-06-09 18:01:12 · answer #7 · answered by Kathleen K 7 · 0⤊ 0⤋