English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

3 answers

This question has a description that goes before it. Without that the question is meaningless.

2007-06-09 17:52:23 · answer #1 · answered by Dr D 7 · 1 0

The change of height of your projectile is:
Δy(t) = vsinθt - ½gt^2
where v is your initial speed in meters per second, θ is the angle that your projectile is fired from the horizonal, t is the time in seconds, and g is the gravitational acceleration (9.8 m/s^2 on Earth). Without giving me any initial conditions, it is hard to describe the behavior of the projectile.

2007-06-10 00:36:35 · answer #2 · answered by Jeff 3 · 0 0

Insufficient data.

2007-06-10 01:03:53 · answer #3 · answered by Anonymous · 0 0

fedest.com, questions and answers