When a 60 kg person climbs into a 1020 kg car, the car's springs compress vertically by 2.9 cm. What will be the frequency of vibration when the car hits a bump?
2007-06-09 13:11:25 · 2 answers · asked by tjmierzwa 2 in Science & Mathematics ➔ Physics
Natural frequency in rad/s of a spring mass system = sqrt(k/m). You have m = 1080, and k = f/x, f being 60*g and x = 2.9 cm. Go.
2007-06-10 02:17:11 · answer #1 · answered by kirchwey 7 · 0⤊ 0⤋
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2016-12-12 16:34:32 · answer #2 · answered by ? 3 · 0⤊ 0⤋