What would the equation be of a straight line that passes through the points (1,1) and (3,3) ??

Answer 1

General form of a straight line is y = mx + b, where m is the slope. The slope of a line is (y2-y1)/(x2-x1), which in this case is (3-1)/(3-1) = 1. So your equation is y = x + b.

What is b? Just plug in one of your (x, y) pairs and solve for it:

1 = 1 + b, so b= 0. Your equation is y = x!

Answer 2

You're missing a verb, but I digress.

The slope of the line would be (3-1) / (3-1) = 1. So the equation is in the form of y = 1*x + b. To find b, plug in a point and solve for b. 1 = 1 + b, so b = 0. So the equation is simply y=x.

Answer 3

Since Y is always equal to X in this example the slope of the graph is one and also Y=0 when X=0.
The equation is Y=1X+0
which would normally be simplified to: y=x

Answer 4

first find the slope by using this formula (y2 - y1)/(x2 - x1)
(3-1)/(3-1) = 2/2 = 1. So the slope is one.
use the formula y=mx + b, where m is slope and b is y-intercept
so far we have y=1x, or y=x. Now you have to find the y-intercept. To do this substitute 0 for x, and find y.
y=0. that was easy, so your y-intercept is 0.
your equation now is y=1x + 0... this is y=x.

Answer 5

m=1 so y=mx=x so y=x (m=3-1/3-1=2/2=1)

Answer 6

So we know the following:

y=x+(1-1)
y=x+(3-3)

so.... y=x

Answer 7

slope m=(3-1)(/3-1)=1
y=x+b
3=3+b
b=0
y=x

Answer 8

well, I know that you use the equation y-k=(x-h)squared. and... you'd plug in the numbers... but, I'm not sure. But hey, I gave you an idea. =)

Answer 9

y=x

because 3=3
and 1=1

we could simply go on forever....
but i decided not to...

Answer 10

it would simply be x=y as the points have x and y equal.