how many zeros are at the end of 50?

Question

dealing with factorials

Answer 1

There is one zero at the end of 50. If you meant how many zeroes there are at the end of "50!", that's another story. I get twelve.

An integer ends in n zeroes if and only if it's a multiple of 10^n. To find n, we need to see how many 10s we can factor out of 50!. We can do this by factoring out a 10, or factoring out (2*5).

There are five exact numbers between 1 and 50 that are multiples of 10 (10, 20, 30, 40, 50). If we factor a 10 out of each of these, we're left with 1, 2, 3, 4, 5. That gives us a 10^5 we can factor out of 50!. Though 50 has an extra 5 as a factor. Remember this for later on.

There are also five other numbers that have 5 as a factor (5, 15, 25, 35, 45). In fact, 25 has two factors of 5, so combining these with the 5 form 50 gives seven factors of 5 within 50! when we get rid of the tens. Now we just need seven 2s to go with these seven 5s. Any even number has 2 as a factor, so we can certainly factor out seven 2s from what's left over in 50!. This means you have 5+7= twelve 10s you can factor out of 50!. So it ends in twelve zeroes.

Answer 2

Maybe you want to know how many zero are at the end of 50 factorial (50!). We would have to count how many numbers and products end in a multiple of 10. Let's see:

numbers: 10, 20, 30, 40 (results in 4 zeroes)

products: 5, 15, 35, 45 (times an even number results in 4 more zeros)

products: 25, 50 (times 6, 8 results in 4 more zeroes

I suppose that the answer is that 50! ends in 12 zeroes.

Answer 3

Do you mean 50! ?
12.
there are 5 number ending in 5 & 5 more ending in 0. 25 & 50 both hace 5² as factors for a total of 5^12. there are far more then 2^12 so 5's are limiting.

Answer 4

if you mean at the end of 50!

then 12

this is because

you count the number of fives. (5 times an even number = 0 at the end) By fives, I mean if you prime factorize all of the numbers, how many come up.

so, there is 5, 10, 15, 20, 25 (which has two fives because it is 5 x 5), 30, 35, 40, 45, 50 (which also has two fives : 5x5x2)

that is 12 total zeroes

Answer 5

Your question is a bit vague but I will answer it based on what you have asked.

There is 0 zero's at the end of 50. However at the end of 5, there is 1 zero. But if you counting significant figures, than there are no zeros at the end of 5 or 50 for that matter since the present zero is simply a place holder.

Answer 6

I think 50 factorial has 14 zeroes based on taking a quick shot at it with EXCEL

Answer 7

50! =
304140932017133780436126
081660647688443776415689
60512000000000000

That's 12 zeros

Answer 8

The question is unclear. there is one zero at the end of "50". However, 50! = 3.0414093201713378043612608166065e+64
so there could be a fair number of zeros, in fact if one rounded it to 3e+64, there would be 64 zeros

Answer 9

ummmm 0

Answer 10

well, there are infinity if you think about it. i.e.: 50.000000....
you can have infinity zeroes there because 50.0000... = 50.

but factorials.... i dunno