want to have a sex with a man who is faster than a speeding bullet? It would be over before it started.
2007-06-09 08:54:59 · 8 answers · asked by enzyme 305 3 in Entertainment & Music ➔ Polls & Surveys
But one of his Super powers is stamina, so true...he may be fast but he'd be ready to go again...and all night! Maybe we could add one Super Power to him...G-Spot Finder.
Although this would mean I'd have to get rid of my kryponite headboard.
2007-06-09 10:07:34 · answer #1 · answered by Cyndie 6 · 4⤊ 0⤋
I've never known the character to be interested in anyone besides Lois Lane but had dated Lana in the past.
2007-06-09 08:58:58 · answer #2 · answered by retrodragonfly 7 · 0⤊ 0⤋
That would explain why the invisible women turned invisible , perhaps she wasn't into the slam , bam thank you mam performance of superman : )
2007-06-09 10:02:49 · answer #3 · answered by Anonymous · 1⤊ 0⤋
Well, for one thing, the woman would have to get on top....
You have to figure that if he were on top, with every thrust he'd ram her head right through the wall...
Also, i'd assume he'd pull out....otherwise the force of his "SuperCum" would probably be like turing on a firehose..... not a pretty picture...
2007-06-09 08:59:09 · answer #4 · answered by Anonymous · 6⤊ 1⤋
Oh, he's so big and strong. Yeeeee ow. I take him. He man of steel right? Oooooooh. I take his bullets any time.
Long as he's not tooooo big.
2007-06-09 09:06:50 · answer #5 · answered by Anonymous · 0⤊ 0⤋
Well if he's that fast..... then I'll just have to visit the fortress of solitude. *sigh*
2007-06-09 08:59:46 · answer #6 · answered by Marianne not Ginger™ 7 · 1⤊ 0⤋
well...He's got fingers to finish the job...And a tongue ! LOL
2007-06-09 08:58:38 · answer #7 · answered by Violation Notice 6 · 4⤊ 0⤋
Well, if you get a load of his outfit, I doubt he did well with any of the ladies.
2007-06-09 11:40:09 · answer #8 · answered by Anonymous · 3⤊ 0⤋
i guess lex luther finished up and thats why theyre enemies.....
2007-06-09 09:05:50 · answer #9 · answered by Anonymous · 1⤊ 0⤋