How would you solve for this?

Question

3/p +5/m=2
and you solve for m
would you start with this
(3+p)+(m+5) all divided by pm or not?
very confused

Answer 1

As my algebra teacher drummed into me...

"What you do to one side, you do to the other."

Multiply both sides by m.

This gives 3m/p + 5 = 2m

Multiply both sides by p.

This gives 3m + 5p = 2mp

Move the M's to one side, this gives 5p = 2mp + 3m

which is equal to 5p = m(2p +3)

Divide both sides by (2p+3)

m = 5p/(2p+3)

Answer 2

3/p +5/m=2
As you want to solve for m, isolate m on the left hand side of the equals sign, and collect all the other terms on the right.
Subtract 3/p from each side:
5/m = 2 - 3/p
m is now isolated, but it is in the denominator, and you want it in the numerator. To do that, you need to take the reciprocal of each side.
Before you can do that, you need the RHS to be in the form A/B rather than A - B/C.
Put all the terms on the RHS over a common denominator:
5/m = (2p - 3)/p
Now take reciprocals:
m / 5 = p / (2p - 3)
Multiply both sides by 5 to obtain m alone on the left:
m = 5p / (2p - 3).

Answer 3

OK treat the 3/p as one term and move it over. Don't try to divide with the p because you are solving for m.

So you end up with 5/m = 2 - 3/p

Now solve for m by multiplying the whole other side by 5.

m =5 * (2-3/p)

Answer 4

The idea is to get the variable for which you wish to solve on one side of the equation... eventually all by itself.

1) Multiply both sides by m
3m/p + 5 = 2m

2) Multiply both sides by p
3m + 5p = 2mp

3) Add -3m to both sides
5p = 2mp - 3m
Now m's on one side of the equation and can be "factored out."

4) Apply the distributive property of multiplication over addition, to wit: a(b+c)=ab+ac, to the right side of the equation
5p = (2p-3)m

5) Multiply both sides by 1/(2p-3)
5p/(2p-3) = m

Answer 5

Isolate m from other variables first.

5/m = 2 - (3/p)

Get the 5 outta there.

1/m = (2/5) - (3/5p)

Let's combine the denominator of the right side.

1/m = (2p-3)/5p

Now we flip the numerator and denominator to get just m.

m= (5p)/(2p-3)

Voila!

Answer 6

1. rearrange to 5/m = (2-3/p)
2. multiply both sides by m and divide both sides by (2-3/p)
3 answer is m = 5 / (2-3/p)

Answer 7

first you will substract3/p on both sides.
to give you
5/m = 2 - 3/p then cross multiply.

to get 5p/(2p - 3) = m/1 = m

Answer 8

3/p +5/m=2 multiply by p m

3m + 5 p = 2 p m

3m - 2pm = - 5p

m( 3 - 2 p ) = -5p

m = -5p / ( 3 - 2 p )

Answer 9

Just pull out the p and m
1/(p+m)(3+5)=2

times by (p+m)
8=2(p+m)

Divide by 2
8/2=p+m
4= p+m

Subtract p
4-p=m

Answer 10

3/p +5/m=2

Multiply both sides by pm

3m + 5p = 2pm

3m - 2mp = -5p

factor out an m

m(3 - 2p) = -5p

m = -5p/(3 - 2p)

m = 5p/(2p - 3)
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