English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

5p^3t^2 + 25p^2t^3 - 30pt^4

i cant solve it

2007-06-09 07:58:11 · 5 answers · asked by BOL3N$ HOODPiiNC3$$ 1 in Science & Mathematics Mathematics

5 answers

I believe you are referring to the GCF - greatest common factor.
Look at the numbers first, ther GCF of5, 25, and 30 is 5.
Now look at the powers of p - the smallest will be the GCF, so you have p.
Now look at the powers of t, the lowest is t^2.
Thus the GCF is 5pt^2

2007-06-09 08:02:59 · answer #1 · answered by MathProf 4 · 0 0

5p^3t^2 + 25p^2t^3 - 30pt^4
Every term has a factor of 5, plus some p's and t's.
Take out as many as you can.

= 5pt^2(p^2 + 5pt - 6t^2)
Now factor what's left

= 5pt^2(p - t) (p + 6t)

2007-06-09 08:04:08 · answer #2 · answered by Steve A 7 · 0 0

Lets see, theres a multiple of 5 in each term, theres a P in each term (but only one in the last) , and theres at least a t^2 in each so........ factored would be....

5pt^2(p^2t + 5pt -6 t^2)

answer only requires the GCF so its 5pt^2
hope it helps

2007-06-09 08:54:33 · answer #3 · answered by Monta C 2 · 0 0

GCF= 5pt^2

5pt^2(p^2+5pt-6t^2)

5pt^2(p+6t)(p-t)

2007-06-09 08:04:11 · answer #4 · answered by Dave aka Spider Monkey 7 · 0 0

GCF: 5pt^2


5pt^2 (p^2 + 5pt - 6t^2)

2007-06-09 08:02:08 · answer #5 · answered by      7 · 0 0

fedest.com, questions and answers