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4 answers

Try to graph the question with possible answers ...

(-4,2) and (0,6) could this be perpendicular.
(-2,1) and (0,-2) could this be parallel.

2007-06-09 05:27:03 · answer #1 · answered by Anonymous · 0 0

one way is to compute the slopes immediately utilising m=(y1-y2)/(x1-x2). With the 1st set of things we've (2-(-4))/(-4)=-6/4=-3/2 and the 2nd set supplies us m=(3-(-3))/(4-(-5))=6/9=2/3. those are unfavourable reciprocals so as that they are perpendicular. yet differently is to extra wholesome those pairs into the component-slope formula for immediately lines - y=mx+b. the place m is the slope and b is the y-intercept. Then use the certainty that parallel lines have same slopes at an identical time as perpendicular lines have slopes that are unfavourable reciprocals of one yet another. With (0,-4) we've -4=0m+b so b is -4. With (-4,2) we've 2=m(-4)-4 so m=-6/4=-3/2. we now have y=(-3/2)x-4. Checking: 2=(-6/4)(-4)-4 = 6-4=2 ok and -4=0-4 ok For the different pair we've a million) 3=4m+b and a pair of) -3=-5m+b and subtracting the equations we get 6=9m m=6/9=2/3 word we don't would desire to bypass any extra suitable on the grounds that all of us comprehend the slope. Now word that the -3/2 slope of the 1st equation is the unfavourable reciprocal 2/3 so the lines are perpendicular. yet i like to learn my artwork so permit's proceed with the 2nd equation. utilising (4,3) we've 3=(2/3)4+b so b=a million/3. Now use (-5,-3) to learn. -3=(2/3)(-5)+a million/3=-10/3+a million/3=-3 ok

2016-11-09 22:05:28 · answer #2 · answered by mcmillian 4 · 0 0

Give us points from the other line, and we'll actually be able to give you a sensible answer to the question. Depending on what the other line is, any of the three answers is possible.

2007-06-09 05:15:12 · answer #3 · answered by Bramblyspam 7 · 0 0

Neither.


This question is tricky.

2007-06-09 05:14:07 · answer #4 · answered by to0pid 2 · 0 0

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