Two urns each contain black balls and yellow balls. Urn I contains five black balls and two yellow balls. Urn II contains six black balls and six yellow balls. A ball is drawn from each urn. What is the probability that both balls are yellow?
2007-06-09 04:36:11 · 7 answers · asked by vanessandavid 1 in Science & Mathematics ➔ Mathematics
P ( both yellow ) = (2/7)*(6/12) = 1/7
2007-06-09 04:39:57 · answer #1 · answered by Anonymous · 0⤊ 0⤋
For the first urn, 2/7 for the yellow balls. For the second urn, 1/2 for the yellow balls. For both to be yellow, multiply the two probabilities, 2/7 x 1/2 = 1/7.
2007-06-09 04:44:49 · answer #2 · answered by TitoBob 7 · 0⤊ 0⤋
The probability of drawing a yellow ball in urn I is 2/7
The probability of drawing a yellow ball in urn II is 6/12
These events are mutually exclusive, the multiplication rule applies.
So the probability of a yellow ball from each is (2/7)(6/12) = 12/84 = 1/7
2007-06-09 04:45:28 · answer #3 · answered by cvandy2 6 · 0⤊ 0⤋
Pr(yellow ball from Urn 1)=2/7
Pr(yellow ball from Urn 2)=6/12=1/2
Therefore
Pr(2 yellow balls)=(2/7)*(1/2)=1/7
2007-06-09 04:41:21 · answer #4 · answered by Apple 1 · 0⤊ 0⤋
Probability
= 2/7 * 6/12
= 1/7
2007-06-09 04:40:18 · answer #5 · answered by to0pid 2 · 0⤊ 0⤋
1/7
2007-06-09 04:42:13 · answer #6 · answered by rubu 2 · 0⤊ 0⤋
1/7.
2007-06-09 04:43:06 · answer #7 · answered by ag_iitkgp 7 · 0⤊ 0⤋