2q^2 + 3q + 20 = 2q^2 - 6q
3q + 20 = -6q
9q + 20 = 0
9q = -20
q = -20/9
you were close, you just forgot the negative
2007-06-09 04:24:37
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answer #1
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answered by hawkeye3772 4
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q(2q+3) +20 = 2q(q-3)
2q² + 3q + 20 = 2q² - 6q
group all the q's to the left side,
2q² - 2q² + 3q + 6q = -20
9q = -20
q = -20/9
2007-06-09 04:32:12
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answer #2
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answered by jurassicko 4
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expand to this. . .
2q^2 + 3q + 20 = 2q^2 - 6q
cancel the 2q^2 on each side and add 6q to both sides and subtract 20 from both sides
9q = -20
q = -20/9
2007-06-09 04:23:16
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answer #3
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answered by Tony D 1
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q(2q + 3) + 20 = 2q(q - 3)
2q² + 3q + 20 = 2q² - 6q
2q² + 3q + 20 - 2q² = 2q² - 6q - 2q²
3q + 20 = - 6q
3q + 20 + 6q = - 6q + 6q
9q + 20 = 0
9q + 20 - 20 = 0 - 20
9q = - 20
9q / 9 = - 20 / 9
q = - 20 / 9
- - - - - - - - - -s-
2007-06-09 04:30:09
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answer #4
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answered by SAMUEL D 7
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It's -2/9
2007-06-09 04:48:54
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answer #5
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answered by Thomas V 1
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q(2q+3) +20=2q(q-3)
2q^2+3q+20=2q^2-6q
3q+6q=-20
9q=-20
q=- 20/9
2007-06-09 04:25:25
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answer #6
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answered by Anonymous
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let me check...
q(2q+3)+20=2q(q-3)
to solve this equation, you need to do the distributive property which is like this...
q times 2q plus q times 3 plus 20 equals 2q times q plus 2q times negative 3. here it is...
2 2
2q +3q+20=2q -6q
2 2
-2q -2q
3q+20=-6q
-20 -20
3q=-6q-20
+6q +6q
9q=-20
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9 9
__________________
q=-20/9 or q=20/-9
2007-06-09 04:39:20
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answer #7
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answered by Anonymous
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No it is not. It is definitely -20/9
2007-06-09 04:26:26
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answer #8
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answered by DRA 1
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I agree with the other person... -20/9
2007-06-09 04:21:54
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answer #9
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answered by shekum 2
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I got it to be -20/9....yes...it is -20/9
2007-06-09 04:19:14
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answer #10
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answered by goldenret35 2
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