2007-06-09 04:15:13 · 4 answers · asked by Bret D 1 in Sports ➔ Baseball
SLG == (total bases) / at-bats
conventionally to three decimals.
Total bases == hits + doubles + 2*triples + 3*home runs
2007-06-09 04:20:21 · answer #1 · answered by Chipmaker Authentic 7 · 0⤊ 0⤋
Slugging percentage is defined as the quotient of total bases divided by total at-bats. For instance, if a player's yearly stats are this:
154G
600AB
178 H
103R
35 2B
4 3B
25 HR
104 RBI
.296 BAT AVG.
the slugging percentage would be calculated in this manner:
35 doubles + 4 triples + 25 home runs = 64 extra-base hits. Of the 178 total hits, 64 were for extra bases, meaning that there were 178 - 4 = 114 singles during the year by this batter. Singles count as one base apiece; thus, total bases on singles = 114.
Since doubles count as two bases apiece, 35 X 2 = 70 total bases on doubles.
Triples count as three bses apiece and thus 4 X 3 = 12 total bases on triples.
Finally, home runs count as 4 total bases apiece; thus, 25 X 4 = 100 total bases on home runs.
Total number of total bases for this batter during the year = 114 + 70 + 12 + 100 = 296.
The slugging percentage achieved by this batter would therefore be 296 total bases divided by 600 total at-bats; 296/600 = .493
2007-06-10 14:21:53 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Total number of bases divided by number of at bats. Barry Bonds holds the record for highest slugging percentage in a season at .863 in 2001. Although some people might think that figure is distorted because of the unusual number of walks he receives.
Babe Ruth holds the next highest slugging pct. for a season at .847 in 1921.
2007-06-09 04:36:54 · answer #3 · answered by crazydave 7 · 0⤊ 0⤋
The same rules as batting average except doubles count double, triples count triple, and homers count times four.
2007-06-09 04:54:00 · answer #4 · answered by Menehune 7 · 0⤊ 0⤋