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Hello,

I need to solve physics problem which is described below.

There is a gun which mass is M = 4 kg. The length of the gun's barrel is l = 50 cm. I need to find the average kick force while shooting the bullet which mass is m = 5g. The speed of bullet when it leaves the gun's barrel is v = 930 m/s.

Thanks in advance.

2007-06-08 23:25:53 · 2 answers · asked by Pythagor 1 in Science & Mathematics Physics

2 answers

Velocity of the bullet just before firing = 0

Velocity of the bullet as it leaves the gun = 930 m/s

Distance over which the acceleration took place = 50 cm

Let us calculate the acceleration using the formula

v^2 - u^2 = 2as where s is the distance, a is the acceleration, v is the final velocity and u the initial velocity

930^2 - 0 = 2 X a X 0.5 (length is to be converted into meters)

a = 930 X 930 m/sec^2 = 864900 m/sec^2

mass of the bullet = 5 g = 0.005 kg

Force F = mass X acceleration

= 0.005 X 930 X 930

We know from Newton's third law of motion that action and reaction are equal and opposite. We neglect the frictional forces.

Reaction = 0.005 X 930 X 930

= 4324.5 N

This will lead to a backward acceleration of

4324.5 / 4 = 1081.125 m/sec^2

2007-06-08 23:56:15 · answer #1 · answered by Swamy 7 · 0 0

the galaxies rotate at speeds inconsistent with their obvious mass is considering we do see it all. I am regarding it as being the theoretical Dark Matter. There are very powerful proofs that suggests that darkish subject exist. One the is the inconsistent velocity of and obvious mass. darkish subject makes up approximately seventy five% to eighty% of the problem within the Universe...

2016-09-05 08:50:55 · answer #2 · answered by ? 4 · 0 0

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