Write an equation for a circle with center at P(2, -5) and a diameter of 8 units.
(x - 2)^2 + (y - 5)^2 = 64
(x + 2)^2 + (y + 5)^2 = 8
(x - 2)^2 + (y + 5)^2 = 16
(x + 2)^2 + (y - 5)^2 = 16
2007-06-08 20:40:31 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(x-a)^2+(y-b)^2=r^2.where(a,b) center,r radius of a circle.
here r=diameter/2=8/2=4
and center(2,-5)
so a= 2,b= -5
hence equation for a circle with center at P(2, -5) and a diameter of 8 units becomes
(x-2)^2+(y+5)^2=16
2007-06-08 21:00:44 · answer #1 · answered by chapani himanshu v 2 · 0⤊ 0⤋
(x - 2)² + (y + 5)² = 4²
(x - 2)² + (y + 5)² = 16
THIRD ANSWER
2007-06-08 21:02:15 · answer #2 · answered by Como 7 · 0⤊ 0⤋
24 or 75. between that
2007-06-08 20:43:42 · answer #3 · answered by Anonymous · 0⤊ 0⤋
wtf's with algebra
I HATE ALGEBRA!!!!
its everywhere =S
2007-06-08 20:42:27 · answer #4 · answered by Anonymous · 0⤊ 1⤋