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a. 2x+y+4=0
b. x-y+4=0
c. x-2y+7=0
d. 2x+y-8=0

2007-06-08 16:06:52 · 5 answers · asked by yaro l 1 in Science & Mathematics Mathematics

5 answers

x-2y-6=0
2y=x-6
y=(1/2)x-6

Slope is 1/2. The perpendicular slope would be the negative reciprocal of this fraction, so it would be -2. Now you use the point-slope linear equation format (y-y1=m(x-x1)) to find the other equation.

y-2=-2(x--3)
y-2=-2x-6
2x+y+4=0

Answer is A.

2007-06-08 16:12:42 · answer #1 · answered by Tha Nurd 3 · 1 0

The equation we are given could be rewritten as: 2y = x - 6 y = a million/2x - 3 so the slope is a million/2. consequently the perpendicular line could have a slope of -2. so the equation of the line is y = -2x + b. to locate b, we plug interior the element given. 2 = -2(-3) + b 2 = 6 + b b = -4 so the equation of the line is y = -2x - 4. so the respond is A. desire this permits.

2016-10-09 12:53:51 · answer #2 · answered by ? 4 · 0 0

x - 2y = 6
2y = x - 6
y = (1/2).x - 3
m = 1/2
Gradient of perpendicular = - 2
y - 2 = (-2).(x + 3)
y - 2 = - 2x - 6
2x + y + 4 = 0
ANSWER a.

2007-06-08 21:44:59 · answer #3 · answered by Como 7 · 1 0

a

2007-06-08 16:13:27 · answer #4 · answered by steffers27 5 · 1 0

a.

2007-06-08 16:10:53 · answer #5 · answered by Anonymous · 1 0

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