a skier on a slope inclined at 4.7 degrees to the horizontal pushes on ski poles and starts down the slope. The initial speed is 2.7 m/s. The coefficient of kinetic friction between skis and snow is 0.11. Determine how far the skier will slide before coming to rest.
2007-06-08 16:05:47 · 3 answers · asked by Malvern100 1 in Science & Mathematics ➔ Physics
cant be solved cause u dont have his/her mass.
2007-06-08 16:19:45 · answer #1 · answered by M!z0 3 · 1⤊ 3⤋
a = g [ sin (θ) - μcos (θ) ]
μ = coefficient of kinetic friction.
a = 9.8 [ sin (4.7) - 0.11cos (4.7) ]
a = - 0.27m/s^2
so u know acceleration and the initial velocity, now use the kinematics equation:
x = ( - Vi^2 ) / 2a
x = [ - (2.7^2) / 2 ( - 0.27) ]
x = 13.4m
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mass cancels out
2007-06-08 23:17:00 · answer #2 · answered by driftaddict87 4 · 1⤊ 0⤋
a â 9.80665(sin4.7 - 0.11cos4.7)
a â -0.2715618 m/s
s = (0 - 2.7^2)/(2*(-0.2715619))
s â 13.422 m
2007-06-08 23:43:23 · answer #3 · answered by Helmut 7 · 1⤊ 0⤋