How do you solve 6x-3x+x=-128?

Answer 1

6x-3x+x=-128
3x+x=-128
4x=-128
x=-32

Answer 2

Hi,

The first step with these problems is to always try to combine like terms so that the problem solving becomes very easy. On the left hand side, add/subtract the x's you have. 6x - 3x = 3x therefore it becomes 3x + x which is 4x. Now the problem becomes:

4x = -128

Divide by 4 on both sides of the equation

x = -32 <==== FINAL ANSWER

I hope that helps you out! Please let me know if you have any other questions!

Sincerely,

Andrew

Answer 3

add the common terms which is 6x plus negative 3x makes 3x plus x equals 4x. 4x equals negative 128 divide negative 128 by positive 4 and thats ur answer

Answer 4

Do it step by step.

6x-3x+x=-128 (Do the 6x-3x)
3x+x=-128 (Do the 3x+x)
4x=-128 (Divide both sides by 4)
x=-32

Answer 5

6x - 3x + x = -128

add like terms
4x = -128

divide 4 for both sides
x = -32

Answer 6

I guess you were not paying attention in class. Combine the terms on the left side of the equation; that would make 4X. Divide both sides by 4X; that leaves 1= -128 divided by 4X. the right side resolves to X= - 32.

Answer 7

6x-3x+x=-128

1st combine like terms on left side

4x=-128

2nd divide both sides by for to isolate variable
4/4x=-128/4

Fours cancel and you are left with x=-32

Hope that helped!

Answer 8

6x-3x+x=-128
4x = -128
x = -128/4
x = -32

Answer 9

first, combine the like terms:

6x-3x+x=-128
3x+x=-128
4x=-128

then solve:

x=-128/4
x=-32

Answer 10

6x-3x+x=-128
7x-3x=-128
4x=-128
x=-128/4
x=-32