Aa x Aa -- AA, Aa, aA, aa
Oh, 50%
It's not 25% because the AA and aa are not heterozygous, they are homozygous
2007-06-08 14:22:11
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answer #1
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answered by helpfulhannah 4
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Do a punnet square to figure this one out
Say the trait is represented by the letter 'b'
B= dominant, b=recessive
Bb x Bb
BB Bb
Bb bb
2 out of every 4 offspring in the next generation may be born heterozygous for that trait. 2/4= 50%
2007-06-08 14:30:33
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answer #2
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answered by monica_dietz@sbcglobal.net 4
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Definitely 50. If you do a Punnett square, you get one homozygous dominant, two heterozygous dominant, and one homozygous recessive. Therefore, it has a 50% chance of being heterozygous for the trait. Hope it helped!
2007-06-08 14:25:12
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answer #3
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answered by xl tainted xlove 2
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TT Tt
Tt tt
Your Answer is 50% Heterozygous, 25% Homozygous TT, 25%Homozygous tt
2007-06-08 14:24:28
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answer #4
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answered by Thomas 2
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It is 50% chance bcoz,
TT=25% (tall)
tt=25% (dwarf)
Tt=50% (intermediate) It is in heterozygous condition.
2007-06-08 15:07:09
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answer #5
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answered by rubynama 2
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50% would be heterozygous, 25% would be homozygous dominant and the other 25% would be homozygous recessive.
2007-06-09 08:47:33
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answer #6
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answered by dlg3579 3
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I think it is 25.
or maybe its 50 lol
its not the other 2 though.
2007-06-08 14:16:19
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answer #7
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answered by Cori 4
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b. if the gene for the trait of the parents are, say, AB, then the possible combinations are: AA AB AB BB so the answer is 1/4, or 25%.
2016-05-20 06:18:44
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answer #8
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answered by ? 3
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It is definitely 50.
Just draw out a simple Punnet square. Two of the squares show heterozygotes. Two show homozygotes.
2007-06-08 14:24:20
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answer #9
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answered by Elsie 5
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There is a 25% chance for TT, 25% chance for tt, and 50% chance for Tt.
2007-06-08 14:28:32
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answer #10
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answered by Anonymous
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