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Please hurry this is urgent...

a) 1 2 3 4 5 6 7 8 = 2003
Use the symbols + - x and / once each to make the statement true


b) 7/A = B*C / (D*E) + F*G / (5*H)
Use the digits 0 through 9 once each (5 and 7 already used) to replace the letters and make the statement true

2007-06-08 13:47:09 · 3 answers · asked by Rokko211 2 in Science & Mathematics Mathematics

3 answers

I don't know about a) yet, but b) is plainly impossible.

A can't be zero, otherwise 7/A would be undefined.
D, E, and H can't be zero either, or you have a 0 denominator.
Hence, either B, C, F, or G must be zero.

Either way, the equation turns into either:
7/A = BC/DE
or
7/A = FG/5H

Cross multiply these to get either:
7DE = ABC
or
7*5H = AFG

Either way, the left side of the equation has a factor of 7.
For the equality to hold, the right side must also have a factor of 7. However, this is impossible, given that ABCDEFGH must be the numbers 01234689 in some order.

2007-06-08 14:02:10 · answer #1 · answered by Bramblyspam 7 · 0 0

i am not doing your homework unless u do mine first . who ruled china in the fifth century?

2007-06-08 20:55:05 · answer #2 · answered by Anonymous · 0 0

Can u plz post thie question on http://www.tutorbuddy.org I will answer as soon as u post

2007-06-08 20:53:44 · answer #3 · answered by Anonymous · 0 3

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