2007-06-08 13:39:47 · 8 answers · asked by Bert S 2 in Science & Mathematics ➔ Mathematics
(x+11)(x-1)(x-3) =
(x² - x + 11x - 11)(x-3) =
(x² + 10x - 11)(x-3) =
x³ - 3x² + 10x² - 30x - 11x + 33 =
x³ + 7x² - 41x + 33
2007-06-08 13:44:14 · answer #1 · answered by MathGuy 6 · 0⤊ 0⤋
I assume you mean: (x+11)(x-1)(x-3)
= [(x+11)(x-1)] (x-3)
= (x² - x + 11x - 11) (x-3)
= (x³ + 10x -11) (x-3)
= x³ - 3x² + 10x² - 30x - 11x + 33
= x³ + 7x² - 41x + 33
2007-06-08 20:52:33 · answer #2 · answered by jurassicko 4 · 0⤊ 0⤋
product is (x+11) (x-1) (x-3)
if you simplify this to a polynomial it is not a product anymore
don't even place an equality = because it becomes an equation
2007-06-08 22:52:50 · answer #3 · answered by CPUcate 6 · 0⤊ 0⤋
(x-1)*(x-3)==x^2-4x+3
then multiply this equation by x
then multiply by 11 and add like terms
(x^2-4x+3)*x= x^3-4x^2+3x
(x^2-4x+3)*11= 11x^2-44x +33
now add
x^3+7x^2-41x+33
2007-06-08 20:49:54 · answer #4 · answered by jon d 3 · 0⤊ 0⤋
x^3+7x^2-41x+33
2007-06-08 20:46:34 · answer #5 · answered by lynchy_hi 2 · 0⤊ 0⤋
equale +2 or factor of tow postive it asking for postive or part 2 for scand answer would be adding negathives x-13 to total it , or part 3 could be zero there difffent answers parts to each porblum just get you have used diffent combonations math fuigers....
2007-06-08 20:46:56 · answer #6 · answered by Anonymous · 0⤊ 0⤋
(x+11)(x-1)=x^2+10x-11(x-3)=
x^3-3x^2+10x^2-30x-11x+33
x^3+7x^2-41x+33
2007-06-08 21:13:49 · answer #7 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
(x-1)(x-3)=x²-4x+3
(x+11)(x²-4x+3)=x³-4x²+3x+11x²-44x+33
(x+11)(x-1)(x-3)=x³+7x²-41x+33
2007-06-08 20:45:16 · answer #8 · answered by yupchagee 7 · 0⤊ 0⤋