Homework Help?

Question

Joyce sold 60% of her stamps. Alan bought 40% of the stamps that Joyce sold. After the sale, Joyce had 240 stamps more than Alan. How many stamps have Joyce at first?

Answer 1

Joyce has J stamps. She sold 0.6J stamps.
Alan bought 40% of that, so Alan has 0.4 x 0.6J stamps or 0.24J stamps.
Joyce had 240 stamps more than Alan, so
0.4J - 0.24J = 240.
solving
0.16J = 240
J = 1500 stamps.

checking: Joyce sold 0.6 x 1500 = 900 stamps.
Joyce still have 1500 - 900 = 600 stamps.
Alan bought 40% of that, = 360 stamps.

Joyce has 600 - 360 = 240 stamps more than Alan.

Answer 2

1500

Let S be the initial number of stamps Joyce has. After selling 60%, she has .4S. Alan bought 40% of the stamps Joyce sold, which is .4*.6*S = .24S.

Finally, "Joyce had 240 stamps more than Alan" tells you that:

.4S - .24S = 240
.16S = 240
S = 240/.16 = 1500

Answer 3

Joyce (% left) --> 100% - 60% = 40%
Alan (bought) ---> 40% of 60% = 40% X 60% = 24%
40% - 24% = 16% ----> $240
1% ---> $240 / 16 = $15
100% ----> $15 X 100 = $1500

Note: Qn doesn't tell if Alan did have some stamps on his own at first. Thus, we assume that Alan started with 0 in the first place.

Answer 4

Joyce is left with 40% of her original total.
Alan buys 40% of 60% or 24% of her original total so Joyce has 40%-24%=16% of her original total more than Alan.
16%=0.16
0.16x=240 divide both sides by 0.16
x=1500
Joyce started with 1500 stamps

Answer 5

1500 becuase if 60% of 1500 = 900 and 40% of 900 is 360
so he has 360 stamps
to find out how many she has take 1500 - 900 (because she sold those 900) and that equals 600
then the difference between 600 and 360 is 240

Answer 6

Let x = total stamps Joyce started with.
.6x = stamps sold.
.4*.6x = .24x = stamps Alan bought
.4x = .24x + 240
.16x = 240
x = 1500

Answer 7

u should do ur homework urself .

Joyce have at least 240 stamps.