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Aim remains the same. Ignore air resistance.

2007-06-08 11:33:25 · 10 answers · asked by Alexander 6 in Science & Mathematics Physics

10 answers

Jeezus people, it's just gT=0.98 m/s in the vertical direction. g is gravitational acceleration (9.8 m/s^2) and T is the time interval that the first bullet accelerates downward before the second one leaves the gun (0.1 s). After both bullets are in flight, their downward accelerations are the same, so their relative V does not increase further.

That's on average, since you have to assume the rounds all come out at the same speed too.

2007-06-08 14:11:26 · answer #1 · answered by Dr. R 7 · 3 0

It depends on which stage of the experiment you are talking about. I am assuming that the AK is fired at a target in sight/close proximity. Initially, when the second bullet has just been fired, it would need to accelerate to eventually reach the same velocity as bullet one. This would be the only significant stage where the bullets would have a notable difference in velocity. A detailed analysis will prove that the bullets rarely move at the same velocity, but if you want a practical answer, these minor details can be ignored. By ignoring technical details, it can be said that the bullets travel the same velocity relative to the AK and are stationary relative to one another, for 99% of the journey. They would end up striking the same mark.

2007-06-08 19:12:46 · answer #2 · answered by ? 1 · 0 1

Assuming absolute consistency, at all times the two bullets will be 0.1 seconds apart so it follows that IF their velocity changes in flight there will be a relative velocity between them.

You say ignore air resistance so what else will affect velocity? Maybe gravity. The bullets will accelerate towards the ground so in order to remain 0.1 seconds apart the first one will have a positive relative velocity compared to the second up until it hits the ground.

2007-06-08 19:17:00 · answer #3 · answered by Anonymous · 1 0

Without air resistance, and once the bullets leave the barrel (i.e. acceleration force is exhausted) the velocity of both bullets would be equal and they would remain .1 seconds apart and should strike the ground at the exact same spot.

The bullets would fire .1 seconds apart and should strike the target/ground at exactly the same spot .1 seconds apart.

2007-06-08 18:42:57 · answer #4 · answered by disposable_hero_too 6 · 1 1

Since the second bullet has by definition been exposed to air resistance for a shorter moment, it is always traveling faster than the bullet traveling in the air for a longer moment.
BUT, when surveyed at a specific distance from the barrel, they should manifest the same speed.
Of course, the initial velocity of all bullets is different, so the presumption is that each bullet departs the barrel at the same speed.

2007-06-08 18:47:47 · answer #5 · answered by science_joe_2000 4 · 0 3

I'm sure you can answer this question on your own, being a top contributor....but I'll humor you anyway

Assuming you want the horizontal velocity:

From the equations of motion as derived from Newtons 2ND law: X(t)=.5at^2+vt+x and V(t)=at+v

The veloity of the bullets WILL ALWAYS DIFFER BY .1a where is the intial acceleration of the bullet from the gun


since there is no air Resistance the bullets will keep accelerating forever. THERE VELOCITIES WILL NEVER BE THE SAME.

2007-06-08 19:03:44 · answer #6 · answered by kennyk 4 · 1 2

Zero (after they are done accelerating from the gun powder explosion)
They will travel the same speed 1/10 seconds apart
The velocity of the first one from the perspective of the second one would be zero.

if they were traveling in different lines or accelerating or decelerating or traveling at different speeds they would have relative velocities not equal to zero.

assume all bullets travel the same speed when shot from the same gun and acceleration due to gravity is also negligible.

2007-06-08 18:39:05 · answer #7 · answered by yerffej89 3 · 1 1

The AK-47 fires a 7.62x39mm round at approximately 2330 feet per second. As no round fired produces exactly the same velocity and small variations occur it is not unreasonable to expect that a velocity range of 2290 - 2350 feet per second would be seen with a sufficiently large sampling of ammuntion fired - with the spread even large if the ammuntion was not made with consistancy.

Luke

2007-06-08 18:46:57 · answer #8 · answered by Luke C 2 · 1 2

Really I don't know how many bullets per round, you need to know this. If you know you can easily calculate the frequency ( bullets per sec) or the period (time between two bullets) but not the speed. This is a data for every kind of weapon.

2007-06-08 18:47:23 · answer #9 · answered by The Catcher in the Rye 2 · 0 3

Since they are accelerated out of the gun. Their velocity will peak and then start to decrease. So their relative velocities will start out quite different and as time and distance progress they will approach the same velocity.

2007-06-08 18:46:56 · answer #10 · answered by tfloto 6 · 1 3

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