if something travels at the speed of 149,896,229 meters per second and I need to know how many seconds it will take it to travel 500 meters, do I need to divide 500 with that number? Like 500/149,896,229?
All this workload got me confused...no solutions pls just tell me if I am doing it right!
2007-06-08
11:03:07
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12 answers
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asked by
Nostroμο
2
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Science & Mathematics
➔ Mathematics
Robert L, by saying stupid, I meant that it was stupid of me to get stuck with something so simple...sorry for offending maths LOL. Also, this is HALF the speed of light not 80% of it...
2007-06-10
06:23:05 ·
update #1
To make problems like this easier in the future, get in the habit of keeping track of physical dimensions when doing physics problems. In this case, the speed of light (or any other speed) has the physical dimensions of x/t, where x is length and t is time. So, if you're given 1) a speed, with dimensions x/t, and 2) a distance, with dimensions x, and you want 3) time, with dimensions t, then you know you need to do this:
(x) / (x/t) = t
in order to end up with something with dimensions of time. In other words, in this case, divide the distance by velocity. It may seem awfully simple for this case, but, trust me, with more complicated physics problems, it will make things far easier to understand.
2007-06-08 11:15:49
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answer #1
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answered by Scythian1950 7
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The best way to do these sorts of things I learned in Physics.
You do the same formula with the labels that you use for the numbers...
So - if you know the speed of an object in m/s and you want to know how long it took to go a certain distance in m. Then you would divide the distance by the speed... m/(m/s) = m * s/m = ms/m = s.
If you knew how long it took, and it's velocity, you would multiply the speed times the time m/s * s = ms/s = m
2007-06-08 11:33:11
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answer #2
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answered by Jason K 2
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You are correct. 500 meters divided by 149,896,229 meters per second gives you the number of seconds it takes to travel 500 meters at that speed. So:
500m / 149,896,299 m/sec = ??? seconds
2007-06-08 11:06:04
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answer #3
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answered by Navigator 7
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the cost may well be $9 plus taxs simply by fact there is 15 in each and every so 15 situations 8 may well be a hundred and twenty then upload 15 so which you're able to have sufficient so it would be 9 programs so 9 X 15 is one hundred thirty five you're able to have 5 left over so the cost would be $9
2016-10-07 03:24:49
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answer #4
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answered by ? 4
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Always do a quick sanity check. If you did it the wrong way around you would get an answer of about 300,000 seconds (about 83 hours) . Clearly nonsense.
2007-06-08 11:37:41
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answer #5
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answered by Anonymous
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I'm sorry you think this is stupid. The speed of light is about 186,000 miles per second, so the speed in your problem was about 80% the speed of light. Some particles travel at such speeds.
Again, I'm sorry you think it is stupid.
.
2007-06-08 11:27:55
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answer #6
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answered by Robert L 7
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yes. 500/149,896,229
2007-06-08 11:05:20
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answer #7
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answered by mo m 2
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speed/distance=time
2007-06-08 11:06:47
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answer #8
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answered by Anonymous
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distance = rate x time
so
time = distance/rate
There ya go.
2007-06-08 11:07:20
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answer #9
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answered by Anonymous
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nah-1 m/s
2007-06-08 11:09:10
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answer #10
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answered by Rajagopal N 2
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