alrightly this is the last one (sorry im doing accelerated and it's 12 hrs a week, so we learn alot)
Check to see if the given number is a solution to the given equation:
7y - 1 = y + 3 (if y = 2/3)
2007-06-08 09:43:59 · 11 answers · asked by J O 2 in Education & Reference ➔ Homework Help
how did u get the answer???
2007-06-08 09:51:51 · update #1
yes it is just plug it in into the eqn.
7(2/3) - 1=(2/3)+3
14/3- 1=11/3
11/3=11/3
2007-06-08 09:57:52 · answer #1 · answered by caligirl 2 · 1⤊ 0⤋
Yes!
All you have to do is move all the terms to one side of the equation so that one side or the other is equal to 0. Then plug in your y value, y = 2/3, and see if the resulting statement is true.
7y - 1 = y + 3
7y - y -1 - 3 = 0
6y - 4 = 0
Now, plug in your y value and see if the left side is equal to the right side. If it is, then your number is a solution.
6 (2/3) - 4 = 0 ?
(6/3)(2) - 4 = 0 ?
(2)(2) - 4 = 0 ?
4 - 4 = 0 ?
0 = 0 !
Hence, y = 2/3 is a solution of the equation.
I put the question marks after each equation because we ask ourselves each time whether the statement is true. When we confirm our supposition, we can put an exclamation point at the end, indicating that the statement is indeed true.
Alternately, what you can also do is plug your y value directly into the equation. If the left side equals the right side, then your value is a solution.
2007-06-08 16:48:53 · answer #2 · answered by MathBioMajor 7 · 3⤊ 0⤋
Yes!
7y-1= y+3
(7 x 2/3)-1= 3 and 2/3
2/3 + 3 = 3 and 2/3
2007-06-08 17:02:37 · answer #3 · answered by Anonymous · 0⤊ 0⤋
if y=2/3 u want to substitute y with 2/3 so now u're equation will look like this
(7*2/3)-1=2/3+3
14/3-1= 2/3+9/3
14/3-3/3= 11/3
11/3=11/3
since both sides of the equation equal each other, the solution y=2/3 is correct.
2007-06-08 17:14:15 · answer #4 · answered by Riki S 2 · 0⤊ 0⤋
So in this case, plus in 2/3 for Y. Does (2/3) + 3 equal 7(2/3) -1? Find a common denomantor for the first one, and do the multiplication first in the second part.
2007-06-08 16:52:31 · answer #5 · answered by Sarah W 3 · 0⤊ 0⤋
7(2/3) - 1 = 2/3 + 3
14/3 - 1 = 2/3 + 9/3
14/3 - 3/3 = 2/3 + 9/3
(14-3)/3 = (2+9)/3
11/3 = 11/3
yes
2007-06-08 16:52:14 · answer #6 · answered by 7 · 1⤊ 0⤋
7y-1=y+3
7y-y=3+1
6y=4
y=4/6 =2/3
2007-06-08 16:54:13 · answer #7 · answered by Anonymous · 0⤊ 0⤋
Yes! If y = 2/3, then this equation is in balance.
2007-06-08 17:07:19 · answer #8 · answered by Carlos R 5 · 0⤊ 0⤋
7y - 1 = y + 3
add 1 to both sides:
7y = y + 4
subtract y from both sides:
6y = 4
divide both sides by 6:
y = 2/3
So the answer is yes!
2007-06-08 16:56:25 · answer #9 · answered by Megkid 1 · 1⤊ 0⤋
yes. substitute y for 2/3
2007-06-08 17:16:57 · answer #10 · answered by Anonymous · 0⤊ 0⤋