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How do you find the arc length of the curve given by the parametric equations below, from the point where t = 1 to the point where t = 2.

x = sin t
y = e^t .

these were the possible solutions in the back of the book to choose from....

a. 4.7

b. 23.7

c. 24.1

d. 49.8

or is it none of these ?

2007-06-08 07:10:10 · 3 answers · asked by Doug 2 in Science & Mathematics Mathematics

3 answers

The arc length formula is
S = INT[1 to 2] {sqrt( (dy/dt)^2 + (dx/dt)^2 ) dt}

I know that's impossible to read in text; you can see it for real at http://en.wikipedia.org/wiki/Arc_length , you just have to scroll down to the parametric version.

2007-06-08 07:16:30 · answer #1 · answered by TFV 5 · 0 0

a = dx/dt
b= dy/dt

arc length =
integral of { square root (a^2 +b^2) } dt from t=1 to t=2

2007-06-08 07:18:33 · answer #2 · answered by ATD66 3 · 0 0

dx = cos t dt
dy = e^t dt
ds= sqrt(cos^2t+e^2t) dt
s= Int(1,2) sqrt(cos^2t+e^2t)dt
I don´t see an easy way to calculate this integral

2007-06-08 07:41:38 · answer #3 · answered by santmann2002 7 · 0 0

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