Problem below. How would you match the polar coordinates with the rectangular coordinates (a - e)?

Question

(2, π/2)

a. (-3^1/2, -1)
b. (3^1/2, -1)
c. (2^1/2, -2^1/2, )
d. (-2^1/2, -2^1/2, )
e. (0, 2)

Answer 1

You could use the equations that relate the polar and rectangular coordinates, or you could plot the point and just observe where it lies with respect to x and y.

Answer 2

To change polar to rectangular coordinates, you take the cosine and sine of the angle (in radians) and multiply these by the magnitude to get x and y.

(2, π/2) becomes (2cos(π/2), 2sin(π/2)) = (0, 2) because cos(π/2) = 0 and sin(π/2) = 1.

So the answer is (e).

Answer 3

enable the oblong coordinates of a factor whose polar coordinates are (r, t) be (x, y). here 't' stands for 'theta'. x = r*cos(t) y = r*sin(t) here r = 2, t = 7? /6 x = 2*cos(7? /6) = 2*cos[? + (? /6)] = -2*cos(? /6) = -2*(?3/2) = -?3 y = 2*sin(7? /6) = 2*sin[? + (? /6)] = -2*sin(? /6) = -2*(a million/2) = -a million So (a) is authentic.

Answer 4

(2,pi/2)= 2i
a)(-3^1/2,-1)=2< -5pi/6 as the angle is taken -pi<@<=pi
b) =2<-pi/6
c)= 2<-pi/4
d)=2<-3pi/4
e) = 2