i need help with this quiestion
(5x+9)^2
2007-06-08 04:56:03 · 10 answers · asked by Is 2 in Science & Mathematics ➔ Mathematics
I'm assuming you mean this whole this squared...
(5x+9)^2
(5x+9)(5x+9)
Now use the FOIL method..
25x squared +45x+45x +81 combine like terms.
25x squared + 90x +81
that will be your final answer.
2007-06-08 05:01:41 · answer #1 · answered by Invisble 4 · 1⤊ 0⤋
(5x+9)^2 = (5x+9)(5x+9)
= 25x^2 +90x+81
Ans x = -9/5
2007-06-08 12:08:18 · answer #2 · answered by Tubby 5 · 0⤊ 0⤋
You solve this like an exponent. Multiply it by an identical number.
5x5=25
x*x=x^2 add the letters together to get the exponent
9x9=81
Answer:
25x^2+81
Or maybe you solve it like a polynominal.
(5x+9) (5x+9)
You multiply first numbers from different parenthesis first, then outside, inside last.
25x^2+45x+45x+81
25x^2+90x+81
2007-06-08 12:05:50 · answer #3 · answered by Kandice F 4 · 0⤊ 1⤋
(5x+9)^2
= (5x+9)(5x+9)
= 5x(5x+9) + 9(5x+9)
= 25x^2 + 45x + 45x + 81
= 25x^2 + 90x + 9
2007-06-08 12:09:17 · answer #4 · answered by topsyk 3 · 0⤊ 0⤋
(5x+9)^2 = (5x+9)(5x+9) = 25x^2+90x+81
2007-06-08 12:08:04 · answer #5 · answered by Anonymous · 0⤊ 0⤋
25x^2+90x+81
2007-06-08 12:29:51 · answer #6 · answered by nunez8823 1 · 0⤊ 0⤋
-9/5
2007-06-08 12:11:24 · answer #7 · answered by jeffm 2 · 0⤊ 0⤋
25x² + 90x + 81
(using rule of "square the 1st,"square" the second,twice the product)
2007-06-08 17:54:40 · answer #8 · answered by Como 7 · 0⤊ 0⤋
(5x+9)^2
25x² + 90x + 81
.
2007-06-08 11:59:33 · answer #9 · answered by Robert L 7 · 0⤊ 0⤋
no you do not. it is very easy!!!
with all do respect to the people who answered, this guy is getting you to do his homework for him. Just look at the number of questions he asked to prove my point.
2007-06-08 12:13:02 · answer #10 · answered by popeye 3 · 1⤊ 0⤋