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R'' + (1/r)R' - λR = 0

where *R* is a function of *r*; find the general form of R(r)

2007-06-08 04:03:15 · 1 answers · asked by WOMBAT, Manliness Expert 7 in Science & Mathematics Mathematics

1 answers

The general solution to this differential equation is:

R(r) = C1(Bessel1(0,r√λ) + C2(1/√π)(Bessel2(0,r√λ)

where C1 and C2 are constants, and Bessel1 and Bessel2 are the Bessel functions of the first and second kind I(z) and K(z).

2007-06-08 04:38:57 · answer #1 · answered by Scythian1950 7 · 0 0

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