2007-06-08 03:44:05 · 5 answers · asked by Kerri L B 1 in Science & Mathematics ➔ Physics
Well, in order to have a hang time of 10 seconds, he must spend 5 seconds going up and 5 seconds coming down, assuming we do not count any time spent hanging from the basket while physically holding onto it. To fall under the influence of gravity at the surface of the Earth for 5 seconds, one must fall through a distance of y = 0.5*gt^2 = 0.5(9.8 m/s^2)(5 s)^2 = 0.5*9.8*25 = 122.5 m, which is longer than the length of a football field. Clearly, Michael Jordan does not jump this high into the air, so his hang time must be less than 10 s.
2007-06-08 03:49:10 · answer #1 · answered by DavidK93 7 · 3⤊ 0⤋
Definitely not.
Once he jumps, gravity is the only force acting on him. The time it takes him to reach his highest point on the way up must equal the time it takes him to come back down, so 5 seconds.
The distance travelled under this situation is calculated using the equation:
distance = 0.5 x acceleration x time^2
acceleration due to gravity is 10 m/s^2, so we have
distance = 0.5 x 10 x 5^2 = 125m
No way is he able to jump that high!
2007-06-08 03:53:16 · answer #2 · answered by David M 2 · 1⤊ 0⤋
Could he have? I suppose so. In an open air stadium. The height of his jump would be about h = 1/2 g(t/2)^2. (125 meters)
Did he? No
2007-06-08 03:47:52 · answer #3 · answered by Anonymous · 0⤊ 0⤋
David M has the best answer there. If he fell for 5 seconds he would be dead. It is less than 1 second.
2007-06-08 03:58:40 · answer #4 · answered by Philip W 2 · 0⤊ 0⤋
IMPOSSIBLE..UNLESS HE WAS DUNKING ON THE MOON
2007-06-08 03:52:14 · answer #5 · answered by DR.BRAZIL 2 · 1⤊ 0⤋