I need to write the equation x(x-15) +56 = 0 in quadratic form and the solve by factoring, I think the answer is -8 and 7 but I am not sure can anyone help?
2007-06-08 02:22:53 · 6 answers · asked by mamacitasue 1 in Science & Mathematics ➔ Mathematics
the answers is 8 and 7
x(x-15)+56=0
x^2-15x+56=0
(x-8)(x-7)=0
therefore:
x=8 and x=7
check:
8(8-15)+56=0: correct
7(7-15)+56=0: correct
2007-06-08 02:30:14 · answer #1 · answered by Patrick Ian M 1 · 0⤊ 0⤋
x=7 or 8
2007-06-08 09:26:52 · answer #2 · answered by Z W 2 · 0⤊ 0⤋
in quadratic form it is x^2 - 15x + 56 = 0
Factors are
(x-8)(x-7) =0 So the facotrs are 8 and 7 and not -8 and 7
2007-06-08 09:25:52 · answer #3 · answered by yashtapmi 2 · 3⤊ 0⤋
x² - 15x + 56 = 0
(x - 8).(x - 7) = 0
x = 7 , x = 8
2007-06-08 13:33:03 · answer #4 · answered by Como 7 · 0⤊ 0⤋
x(x-15) + 56 = 0
x^2 - 15x + 56 = 0
(x-7)(x-8)=0
x=7 and 8
If you want help with factoring I tried to explain it in your other "Algebra help" post. Good luck.
2007-06-08 09:40:38 · answer #5 · answered by agfreak90 4 · 0⤊ 0⤋
x(x-15)+56=0
x^2-15x+56=0
x^2-7x-8x+56=0
(x-7)(x-8)=0
x=7 or 8
2007-06-08 09:28:51 · answer #6 · answered by Anonymous · 0⤊ 0⤋