Let the sum of its digits equal a, the sum of the digits in a equal b, and the sum of the digits in b equal c. What does c equal?
2007-06-07 21:08:31 · 4 answers · asked by Math 7 in Science & Mathematics ➔ Mathematics
two-digit numbers divisible by 9:
a = 9 or 18; b = 9; c = 9
three-digit numbers divisible by 9 (900, 765, 297, 999)
a = 9, 18, or 27; b = 9; c = 9
2222-digit numbers divisible by 9 (too long to list here):
a = 2223 (low) to 19998 (high); b = 9 (low) to 36 (high); c = 9
c ALWAYS equals 9
2007-06-08 01:07:02 · answer #1 · answered by jimbob 6 · 0⤊ 0⤋
c â¡ 9
2007-06-08 04:20:43 · answer #2 · answered by Helmut 7 · 0⤊ 0⤋
9.
Any number divisible by 9 has the sum of its digits also total to 9 or a multiple of 9.
s
2007-06-08 07:24:30 · answer #3 · answered by blind_chameleon 5 · 0⤊ 0⤋
make all the 2222 digits 9... thats it!
2007-06-08 04:22:40 · answer #4 · answered by Avantika D 2 · 0⤊ 0⤋