David and Michael charged Mr. Jimenez $3,000 toremodel his basement.?

Question

David and Michael charged Mr. Jimenez $3,000 to
remodel his basement. To complete the project,
David worked 4 days alone, Michael worked 1 day
alone, and they worked 10 days together. If they
each received the same amount of money for each
day that they worked, how much of the $3,000 did
David receive?
(A) $1,800
(B) $1,750
(C) $1,680
(D) $1,575
(E) $1,200

Answer 1

the ratio of david's working days to michael's
4 : 1
total they work 5 days
to get 10 days
8 : 2
$3000 / 10 days = $300
since David worked 8 days, he should get $300 times 8 days = $2400

Answer 2

Compute man-days for each person. Then divide the $3K by the number of man days. Multiply this result by 14, the number of man-days David worked.

Answer 3

let rate per day be x for both
4x+x+10*2x=3000
25x=3000
x=120
Since David worked for 14 days in all
Therefore, David received
=14*120
=1680
Ans. (c)

Answer 4

c DEFINITELY ADD ALL DAYS IN TOTAL

10 PLUS 10 PLUS 1 PLUS 4 EQUALS 25 THEN DIVIDE INTO 3000 AND FIND DAILY PAY AND THEN TIMES EACH PERSONS AMOUNT OF DAY BY THE PAY

KIM