Split pot.
Each player uses the best five cards available to them, and only those cards.
so the active hand for both players is
8, 8, A, K, 10
The guy who said player 2 wins is wrong.
2007-06-07 17:55:35
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answer #1
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answered by Anonymous
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It is a split pot.
You always pick the best five cards to make a hand. You can only play a kicker if it beats the cards on the board. You can never use a sixth card as a kicker.
So player 1 has:
8 8 A K T
Player 2 has:
8 8 A K T
In order for the kicker to play the board would have to be something like:
8 A K 5 3
Then the best hand would be:
8 8 A K 6, and player 2 would win since player 1 could not beat the board with his 2.
2007-06-08 01:58:39
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answer #2
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answered by ZCT 7
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It is a split pot, you play the best 5 cards out of the 7, so you both have to play your pair of 8's and the A-K-10, your kickers in your hands do not play here.
2007-06-09 20:55:03
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answer #3
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answered by sincity usa 7
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this would be a split pot. You only look at the best 5 cards for each player. in this case they are the same so the pot is divided equally.
2007-06-07 17:52:28
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answer #4
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answered by spotsknight 3
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Best hand is a pair of eights, A, K, 10.
Both players have it and it's a split.
2007-06-07 20:20:51
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answer #5
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answered by Your Uncle Dodge! 7
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Definitely split pot. Both players have the same best hand.
And don't let anybody tell you that you have to cut for high card or roll dice or armwrestle to break ties.
2007-06-08 12:44:35
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answer #6
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answered by Anonymous
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Split pot, best hand for each player and they are even.
2007-06-07 17:55:26
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answer #7
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answered by Max Power 3
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It relies upon on the place you're enjoying. in case you have been enjoying in Los Vegas then the broking is going to chop up the pot cuz its his job yet you nevertheless could have won. purely style in Rank of Texas Holdem palms on any seek engine and you gets an incredible style of effects.
2016-11-07 22:21:42
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answer #8
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answered by trippi 4
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player 2 wins
2007-06-07 19:44:51
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answer #9
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answered by bluerose2223 1
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player 2 wins
2007-06-07 18:45:43
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answer #10
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answered by Anonymous
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